Question

There is an iceberg in the sea (i) Calculate the fraction of iceberg below the surface of water and (ii) Calculate the fraction of iceberg above the surface of water. Given, density of ice $=917kg{m}^{-3}$ and density of sea water $=1.024\times {10}^{3}kg{m}^{-3}$.

Answer 1

$xV{\rho }_{w}g={\rho }_{i}Vg$

$x=\frac{{\rho }_i}{{\rho }_w}$

$x=\frac{917}{1.024\times {10}^3}$

$x=0.295$

fraction $=1-0.895$

$=0.105$