Question

There is an irregular mating population. If the frequency of an autosomal recessive Lethal gene is 0.4 then the frequency of the carriers in a population of 200 individuals is.........
Whats the and & how?

Answer 1

If frequency q of the autosomal lethal is 0.4, then p = 1-q = 0.6.

Following the Hardy-Weinberg equation p^2 + 2pq + q^2 = 1,

p^2 = 0.36, 2pq = 0.48, q^2 = 0.16.

2pq is the frequency of heterozyogte carriers, so 0.48 x 200 = 96 individuals.