Thermally most stable compound is

H C l O_{4}

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H C l O_{3}

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H O C l

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H C l O_{2}

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Solution

The correct option is C $H C l O_{4}$
Decreasing order of thermal stability of oxy acids of chlorine.
$H O C l O_{3} > H O C l O_{2} > H O C l O > H O C l$
In $H O C l O_{3},$ chlorine is in $+ 7$ oxidation state.

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Similar questions

Arrange the following compounds according to the increasing order of oxidation state of chlorine.

$H C l O_{4}, H C l O_{3}, H C l O_{2}, H C l O$

H O C l, H C l O_{2}, H C l O_{3}

H C l O_{4}

H O C l, H C l O_{2}, H C l O_{3}

H C l O_{4}

{H C l O}_{4}

{H C l O}_{3}

{H C l O}_{2}

H O C l

H C l O_{4} < H C l O_{3} < H C l O_{2} < H C l O

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