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Question

Third term in the expression (x+a)7 is

A
7C2x5a2
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B
7C3x4a3
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C
7C4x3a4
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D
7C6x1a6
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Solution

The correct option is A 7C2x5a2
Using pascal triangle, we get
(x+a)7= 7C0x7+ 7C1x6a+ 7C2x5a2++ 7C7a7

The third term is 7C2x5a2

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