Question

Three angles of a seven sided polygon are ${132}^{\circ }$ each and the remaining four angles are equal. Find the value of each equal angle.

• A. ${126}^{\circ }$
• B. ${116}^o$
• C. ${120}^o$
• D. ${140}^o$

Answer 1

The correct option is A ${126}^{\circ }$

Three angles of a seven sided polygon are ${132}^o$ each and the remaining four angles are equal. Let each equal angle is = $x^o$
Sum of total angle = $3\times {132}^o+4\times x^o$
Sum of total interior angles of any polygon = ${180}^o(n-2)$ $={180}^o(7-2)={180}^o\times 5={900}^o$
$3\times {132}^o+4\times x^o={900}^o$
$4x^o={504}^o$
$x^o={126}^o$
Remaining four angles are ${126}^o$