Three angles of a seven sided polygon are 132∘ each and the remaining four angles are equal. Find the value of each equal angle.
A
126∘
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B
116o
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C
120o
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D
140o
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Solution
The correct option is A126∘ Three angles of a seven sided polygon are 132o each and the remaining four angles are equal. Let each equal angle is = xo Sum of total angle = 3×132o+4×xo Sum of total interior angles of any polygon = 180o(n−2)=180o(7−2)=180o×5=900o 3×132o+4×xo=900o 4xo=504o xo=126o Remaining four angles are 126o