Three balls $A, B$ and $C$ of same size but of different masses, are thrown with the same speed from the roof of a building, as shown in figure. Let $v_{A}, v_{B}$ and $v_{C}$ be the respective speeds with which the balls $A, B$ and $C$ hit the ground. Neglecting air resistance, which one of the following relations is correct?

v_{A} > v_{C} > v_{B}

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v_{C} > v_{A} > v_{B}

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v_{A} > v_{B} > v_{C}

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v_{A} = v_{B} = v_{C}

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Solution

The correct option is D $v_{A} = v_{B} = v_{C}$
Since their kinetic energies are equal their final velocities at the time of striking the ground are equal.

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The correct option is D vA=vB=vCSince their kinetic energies are equal their final velocities at the time of striking the ground are equal.

The correct option is D $v_{A} = v_{B} = v_{C}$
Since their kinetic energies are equal their final velocities at the time of striking the ground are equal.