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Standard XII

Physics

Distance

Three block o...

Question

Three block of masses $m_{1}, m_{2}$ and $m_{3}$ are connected by massless string as shown on a frictionless table. They are pulled with a force $T_{3} = 40 N$ . If $m_{1} = 10 k g, m_{2} = 6 k g$ and $m_{3} = 4 k g$ , the tension $T_{2}$ will be

20 N

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40 N

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10 N

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32 N

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Solution

The correct option is D $32 N$
Total mass of system $= 20 k g$
Acceleration of system $= 40 n$
$A = f / m$
$= 40 / 20$
$= 2$
Because string $t_{2}$ pulls $1$ and $2$ blocks
Therefore $t_{2} = (m_{1} + m_{2}) a$
$= 32 N$
Hence,
option $(D)$ is correct answer.

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