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Standard XII

Physics

Wave Speed expression

Three blocks ...

Question

Three blocks of masses $m_{1} = 10 k g$ , $m_{2} = 20 k g$ and $m_{3} = 30 k g$ are on a smooth horizontal table, connected to each other by light horizontal strings. A horizontal force F $=$ 60N is applied to $m_{3}$ towards right. Find
(a) tensions $T_{1}$ and $T_{2}$
(b) tension $T_{2}$ if all of a sudden the string between $m_{1}$ and $m_{2}$ snaps

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Solution

For calculating force use the formula

a= F(net)/total mass

so a= 60/10+20+30

a= 60/60 = 1 m/s

now, if force is applied on 1 body then

tension between 2 and 3 body is

T1=mass x acceleration

= 30x1 = 30 N

and the tension between 1 and 2 body is

T = (30+20)x1 = 50N

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Three blocks of masses m1=10kg,m2=20kg and m3=30kg are on a smooth horizontal table, connected to each other by light horizontal strings. A horizontal force F= 60N is applied to m3 towards right. Find (a) tensions T1 and T2(b) tension T2 if all of a sudden the string between m1 and m2 snaps

For calculating force use the formula a= F(net)/total mass so a= 60/10+20+30 a= 60/60 = 1 m/s now, if force is applied on 1 body then tension between 2 and 3 body is T1=mass x acceleration = 30x1 = 30 N and the tension between 1 and 2 body is T = (30+20)x1 = 50N

For calculating force use the formula

a= F(net)/total mass

so a= 60/10+20+30

a= 60/60 = 1 m/s

now, if force is applied on 1 body then

tension between 2 and 3 body is

T1=mass x acceleration

= 30x1 = 30 N

and the tension between 1 and 2 body is

T = (30+20)x1 = 50N