Three bulbs of $40 W$ , $60 W$ and $100 W$ are arranged in series with $220 V$ . The maximum light is obtained from the bulb of:

40 W

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60 W

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100 W

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Solution

The correct option is A $40 W$
In series combination, current flowing across each element is same.

$∵ P = \frac{I^{2}}{R}$

Since current is same the power dissipation will be higher for the bulb with higher resistance i.e. $40 W$ .
In series combination, the bulb with lower rated power will glow brighter.

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Similar questions

Three bulbs 40W, 60W and 100W are connected to 220V mains. Which bulb will glow brightly if they are connected in series?

You are given 3 bulbs of 40W, 60W and 100 W. Which of them has lower resistance, why

25 W, 40 W, 60 W

100 W

List I	List II
(P) $25 W$	(1) Highest potential differences
(Q) $100 W$	(2) Second highest potential difference
(R) $60 W$	(3) Third highest potential difference
(S) $40 W$	(4) Lowest potential difference

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