Question

three capacitors each of capacitance 4 µF are to be connected in such a way that the effective capacitance is 6 µF. This can be done by connecting
(i) all of them in series
(ii) all of them in parallel
(iii) two in parallel and one in series

Answer 1

Dear Student,


$$\begin{gathered} twoinseriesthenthesetwoinparallelwiththirdone \\ {C}_{eff}=\frac{4*4}{4+4}+4=6microfarad \\ Regards \end{gathered}$$