Question

Three capacitors each of capacitance $9pF$ are connected in series. What is the potential difference across each capacitor if the combination is connected to a $120V$ supply?

• A. $10Volt$
• B. $20Volt$
• C. $30Volt$
• D. $40Volt$

Answer 1

The correct option is D $40Volt$

Using voltage division rule, the potential difference across each capacitor,

$v=\left(\frac{C_1}{C_1+C_2+C_3}\right)\times V=\left(\frac{9}{9+9+9}\right)\times 120=\frac{120}{3}=40V$

Ans:$\left(D\right)$