Question

Three capacitors each of capacity $4\mu F$ are to be connected in such a way that effective capacitance is $6\mu F$. This can be done by

• A. Connecting two in parallel and one in series
• B. Connecting them in series
• C. Connecting them in parallel
• D. Connecting two in series and one in parallel

Answer 1

Answer: (D)

Connecting two in series and one in parallel

For series, $C=\frac{C_1\times C_2}{C_1+C_2}=\frac{4\times 4}{4+4}=2\mu F$
For parallel, $C_{eq}=C^{\prime }+C_3=2+4=6\mu F$