Question

Three capacitors of capacitance $6\mu F$ each are available. The minimum and maximum capacitance which may be obtained are

• A. $6\mu F,18\mu F$
• B. $3\mu F,12\mu F$
• C. $2\mu F,12\mu F$
• D. $2\mu F,18\mu F$

Answer 1

The correct option is D

$2\mu F,18\mu F$

$C_{max}=3\times 6\mu F=18\mu F{C}_{min}=\frac{6}{3}\mu F=2\mu F$