Elimination Method of Finding Solution of a Pair of Linear Equations
Three chairs ...
Question
Three chairs and two tables cost Rs. 1850. Five chairs and three tables cost Rs. 2850. Then the total cost of one chair and one table is
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Solution
Given 2 tables and 3 chairs=Rs.1850 Let cost of 1 chair =Rs.x Cost of 1 table =Rs.y Now, we have 3x+2y=1850×5 ...(i) 5x+3y=2850×3 ...(ii) ⇒15x+10y=9250 ...(1) 15x+9y=8550 .... (2) Subtract (1)-(2), we get y=700. Substitute values of y in (1), we get 3x+1400=1850 ⇒3x=450
⇒x=Rs.150 ∴ total cost of 1 chair and 1 table is 150+700=Rs.850.