Cross-Multiplication Method of Finding Solution of a Pair of Linear Equations
Three chairs ...
Question
Three chairs and two tables cost Rs1,850. Five chairs and three tables cost Rs 2,850. Then the total cost of one chair and one table is
A
Rs 800
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B
Rs 850
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C
Rs 900
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D
Rs 950
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Solution
The correct option is B Rs 850 Let cost of one chair be Rs x and cost of one table be Rs y Now as per the question, 3x+2y=1850 .....(1) 5x+3y=2850 ......(2) Now mutiplying equation (1) by 5 and equation (2) by 3 15x+10y=9250 .....(3) 15x+9y=8550 ......(4) Now subtracting equation (4) from equation (3) ⇒y=700 Put this value in eq (1), ⇒3x+2(700)=1850 3x+1400=1850 3x=450 x=150 Now total cost of 1 chair and 1 table = x+y =150+700=850 So, total cost of 1 chair and 1 table is Rs 850