Three charges q1=1μC,q2=−2μC,q3=2μC, are placed at the vertices of an equilateral triangle of side 1m. The magnitude of net electric force in newton on charge q1 is
A
13.92×10−3N
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B
18.0×10−3N
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C
12.93×10−3N
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D
11.23×10−3N
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Solution
The correct option is B18.0×10−3N
This problem is based on the principle of superposition of electric forces F13=9×109(1×10−6)(2×10−6)12 =18×10−3 F12=9×104(1×10−6)(2×10−6)12 =18×10−3 Fnet on q1 is F =√(18×10−3)2+(18×10−3)2+2(18×10−3)2cos120∘ =18.0×10−3N