Three charges −q1,+q2 and −q3 are placed as shown in Fig. The x-component of the force on −q1 is proportional to
A
q2b2−q3a2sinθ
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B
q2b2−q3a2cosθ
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C
q2b2+q3a2sinθ
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D
q2b2+q3a2cosθ
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Solution
The correct option is Cq2b2+q3a2sinθ
Net force on charge −q1 due to other two charges is →F1=→F12+→F13 →F1=kq1q2b2^i+kq1q3a2(sinθ^i+cosθ^j)
Clearly, the x-component of total force is proportional to q2b2+q3a2sinθ