Three circles touch each other externally . A triangle is formed when the centre s of these circles are joined together . Find the radii of the circles, if the sides of the triangle formed are 6 cm , 8 cm and 9 cm
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Solution
Let ABC be the triangle formed when centres of 3 circles are joined . Given , AB = 6 cm , AC = 8 cm and BC = 9 cm And let the radii of the circles having centers A,B and C be r1,r2andr30 respectively . So, we have r1+r3=8 r3+r2=9 r2+r1=6 Adding all the above equations, we get r1+r3+r3+r2+r2+r1=8+9+62(r1+r2+r3)=23 So, r1,+r2+r3=11.5cm Now, r1+9=11.5(Asr2+r3=9) r1=2.5cm And, r2+6=11.5(Asr1+r2=6) r2=5.5cm Lastly r3+8=11.5(Asr2+r1=8) r3=3.5cm Therefore , the radii of circles are r1=5.5cm and r3=3.5cm