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Question

Three coins are tossed simultaneously 100 times with the following frequencies of different outcomes:
Outcome: No head One head Two heads Three heads
Frequency: 14 38 36 12

If the three coins are simultaneously tossed again, compute the probability of:
(i) 2 heads coming up.
(ii) 3 heads coming up.
(iii) at least one head coming up.
(iv) getting more heads than tails.
(v) getting more tails than heads.

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Solution

The total number of trials is 100.

Remember the empirical or experimental or observed frequency approach to probability.

If n be the total number of trials of an experiment and A is an event associated to it such that A happens in m-trials. Then the empirical probability of happening of event A is denoted byand is given by

(i) Let A be the event of getting two heads.

The number of times A happens is 36.

Therefore, we have

(ii) Let B be the event of getting three heads

The number of times B happens is 12.

Therefore, we have

(iii) Let C be the event of getting at least one head.

The number of times C happens is.

Therefore, we have

(iv) Let D be the event of getting more heads than tails.

The number of times D happens is.

Therefore, we have

(v) Let E be the event of getting more tails than heads.

The number of times E happens is.

Therefore, we have


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