Three coins are tossed simultaneously $200$ times with the following frequencies of different outcomes. If the three coins are simultaneously tossed again, compute the probability of $2$ heads coming up.

Outcome
$3$ heads
$2$ heads
$1$ head
No head
Frequency
$23$
$72$
$77$
$28$

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Solution

We have to find the probability of $2$ heads coming up
Number of times 2 heads come up $= 72$
Total number of times the coins were tossed $= 200$
Thus, the probability of $2$ heads coming up :
$\frac{72}{200} = \frac{9}{25}$ .
Hence, the probability of $2$ heads coming up $\frac{9}{25}$ .

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200

Outcome	$3 h e a d s$	$2 h e a d s$	$1 h e a d$	No head
Frequency	$23$	$72$	$77$	$28$

2

Three coins are tossed simultaneously $200$ times with the following frequencies of different outcomes:

Outcome	$3$ heads	$2$ heads	$1$ head	No head
Frequency	$23$	$72$	$77$	$28$

If the three coins are simultaneously tossed again, compute the probability of $2$ heads coming up.

Outcome	3 heads	2 heads	1 head	No head
Frequency	23	72	77	28

\begin{matrix} O u t c o m e & 3 h e a d s & 2 h e a d s & 1 h e a d & N o h e a d F r e q u e n c y & 23 & 72 & 77 & 28 \end{matrix}

100

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- 38

- 36

- 12

2

3

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