Question

Three coins are tossed simultaneously. What is the probability of getting exactly two heads?
(a) $\frac{1}{2}$ (b) $\frac{1}{4}$ (c) $\frac{3}{8}$ (d) $\frac{3}{4}$

Answer 1

Let H : Head and T : Tail
then the outcomes when $3$ coins are tossed simultaneously are
HHH
HTT
THT
TTH
TTT
THH
HTH
HHT
Thus, the total outcomes are $8$.

Two heads means exactly ($2$ heads)

Favourable cases = (HHT, HTH, THH)
Probability of an even $=\frac{\text{no of favourable cases}}{\text{total number of cases}}$

Thus, required probability $=\frac{3}{8}$

Hence, the correct option is C ($\frac{3}{8}$)