Question

Three coins are tossed simultaneously. What is the probability that they will fall two heads and one tail?

• A. $\frac{1}{3}$
• B. $\frac{1}{2}$
• C. $\frac{1}{4}$
• D. $\frac{3}{8}$

Answer 1

The correct option is D $\frac{3}{8}$

Probability that 1st and 2nd coin will fall head and 3rd tail $=\frac{1}{2}\cdot \frac{1}{2}\cdot \frac{1}{2}=\frac{1}{8}$

Probability that 1st and 3rd coin will fall head and 3rd tail $=\frac{1}{2}\cdot \frac{1}{2}\cdot \frac{1}{2}=\frac{1}{8}$

Probability that 3rd and 2nd coin will fall head and 1st tail $=\frac{1}{2}\cdot \frac{1}{2}\cdot \frac{1}{2}=\frac{1}{8}$

Required probability $=\frac{3}{8}$

D is true