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Question 8
T
hree consecutive integers are such that when they are taken in increasing order and multiplied by 2, 3 and 4 respectively, they add up to 74. Find these numbers.


Solution

Let the three consecutive integers bxx+and x+2.
According to the question,          2x+3(x+1)+4(x+2)=74
2x+3x+3+4x+8=749x+11=74
9x=639x9=639 [Dividing both sides by 9]
x=7
Hence first integer = 7, second integer = 7 + 1 =8 and third integer = 7+ 2= 9.

Mathematics

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