Question

Three dice are rolled. Find the number of possible outcomes in which at least one die shows 5.

Answer 1

Total numbers of dice = 3
$\therefore$ The number of possible outcomes = $6\times 6\times 6=216$ $\therefore$ The number of possible outcomes in which 5 does not appear on any dice $5\times 5\times 5=125$ $\therefore$ Required number of possible outcomes = 216- 125 = 91