Question

Three dice are thrown. What is the probability that the same number will appear on each of them ?

• A. $1/6$
• B. $1/18$
• C. $1/24$
• D. $1/36$

Answer 1

The correct option is D $1/36$

Let us suppose a particular number appears on the three dices,

So, probability $=\frac{1}{6}\times \frac{1}{6}\times \frac{1}{6}=\frac{1}{216}$

Now there can be six different numbers $1,2,3,4,5,6$ so there are six ways,

So, required probability$=\frac{1}{216}\times 6=\frac{1}{36}$

Hence, option D is correct.