Question

Three identical fair dice are rolled once. The probability that the same number will appear on each of them is

• A. $\frac{1}{6}$
• B. $\frac{1}{36}$
• C. $\frac{1}{18}$
• D. $\frac{3}{28}$

Answer 1

Answer: (B)

$\frac{1}{36}$

Total number of ways $=6\times 6\times 6=6^3$
Number of favorable ways $=6$
$\therefore$ Required probability $=\frac{6}{6^3}=\frac{1}{36}$