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Question

Three dice are thrown. What is the probability that the same number will appear on each of them ?

A
1/6
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B
1/18
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C
1/24
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D
1/36
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Solution

The correct option is D 1/36
Let us suppose a particular number appears on the three dices,
So, probability =16×16×16=1216

Now there can be six different numbers 1,2,3,4,5,6 so there are six ways,
So, required probability=1216×6=136
Hence, option D is correct.

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