Question

Three identical dice are rolled the probability that the same number will appear on each of them is

• A. $\frac{1}{6}$
• B. $\frac{1}{8}$
• C. $\frac{1}{36}$
• D. None of these

Answer 1

Answer: (C)

$\frac{1}{36}$

Total ways $=6\times 6\times 6$ favourable ways are 6,
ie., (1,1,1) (2,2,2) (3,3,3) (4,4,4) (5,5,5) (6,6,6)
So, required probability $=\frac{6}{6\times 6\times 6}=\frac{1}{36}.$