Three different containers contain different quantities of a mixture of milk and water whose measurements are $403$ litres, $434$ litres and $465$ litres What biggest measure must be there to measure all the different quantities exactly?

7

litres

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1

litre

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31

litres

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41

litres

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Solution

The correct option is B $31$ litres
Prime factorization of $403, 434$ and $465$ is
$403 = 13 \times 31$
$434 = 2 \times 7 \times 31$
$465 = 3 \times 5 \times 31$
$H . C . F$ of $403, 434$ and $465 = 31$
So, The container of quantity $31$ litres is used to measure all the different quantities exactly.
Hence, C is the correct option.

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Three different containers contain different quantities of a mixture of milk and water whose measurements are 403 litres, 434 litres and 465litres What biggest measure must be there to measure all the different quantities exactly?

The correct option is B 31 litresPrime factorization of 403,434 and 465 is403=13×31434=2×7×31465=3×5×31H.C.F of 403,434 and 465=31So, The container of quantity 31 litres is used to measure all the different quantities exactly.Hence, C is the correct option.

Three different containers contain different quantities of a mixture of milk and water whose measurements are $403$ litres, $434$ litres and $465$ litres What biggest measure must be there to measure all the different quantities exactly?