wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Three identical cells, each of 4V and internal resistance r, are connected in series to a 6-ohm resistor. If the current flowing in the circuit is 2A. The internal resistance of each cell is?


Open in App
Solution

Step 1: Given parameters

Current in the circuit, I=2A

Total emf =3×4=12V

E=WQ

Here,

E is the electromotive force.

W is the work done.

Q is the charge.

Total resistance =6+3r

Step 2: To find

We have to find the internal resistance of each cell

Step 3: Calculation

By using Ohm's law.

I=VR

By substituting the values, we get

2=126+3r2(6+3r)=1212+6r=126r=12-12r=06r=0

Therefore, the internal resistance of each cell is 0Ω.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Intrinsic Property
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon