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Question

Three lines px+qy+r=0,qx+ry+p=0 and rx+py+q=0 are concurrent, if

A
p+q+r=0
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B
p2+q2+r2=pr+rq
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C
p3+q3+r3=3pqr
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D
None of these
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Solution

The correct options are
A p+q+r=0
C p3+q3+r3=3pqr
Given lines px+qy+r=0,qx+ry+p=0
and rx+py+q=0 are concurrent.
∣ ∣pqrqrprpq∣ ∣=0
Applying R1R1+R2+R3 and taking common from R1
(p+q+r)∣ ∣111qrprpq∣ ∣=0

(p+q+r)(p2+q2+r2pqqrpr)=0p3+q3+r33pqr=0
Therefore, (a) and (c) are the answers.

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