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Question

Three liquids with masses m1,m2,m3 are thoroughly mixed. If their specific heats are c1,c2,c3 and their temperatures are T1,T2,T3 respectively, then the temperature of the mixture is:


A
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B
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C
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D
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Solution

The correct option is B

Given, T1,T2 and T3 are the temperature of liquids with mass m1,m2 and m3 with specific heats c1,c2 and c3
Let the final temperature be TC.
Total heat supplied by the three liquids in coming down to 0C is
m1c1T1+m2c2T2+m3c3T3 ......(i)

Total heat used by three liquids in raising temperature from 0CtoTC is
m1c1T+m2c2T+m3c3T .....(ii)
By equating (i) and (ii) we get,
m1c1+m2c2+m3c3)T=m1c1T1+m2c2T2+m3c3T3
or, T=m1c1T1+m2c2T2+m3c3T3m1c1+m2c2+m3c3


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