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Diborane

Three moles o...

Question

Three moles of $B_{2} H_{6}$ are completely reacted with methanol.
The number of moles of boron containing product formed is

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Solution

$B_{2} H_{6} + 6 C H_{3} O H \to 2 B (O C H_{3})_{3} + 6 H_{2}$
1 mole of $B_{2} H_{6}$ mole gives 2 moles of $B (O C H_{3})_{3}$ . So 3 moles of $B_{2} H_{6}$ would give 6 moles of $B (O C H_{3})_{3}$ .

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