Three particles are projected from a tower on inclined plane with same speed $u$ as shown in figure. Mark the correct option from the following

A will collide the inclined plane with more speed than B and C

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B will collide the inclined plane with more speed than A and C

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C will collide the inclined plane with more speed than A and B

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All will collide the inclined plane with same speed

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Solution

The correct option is A A will collide the inclined plane with more speed than B and C
The horizontal component remains same through out motion.
The vertical component of velocity is $u_{y} \propto \sqrt{h}$ where h is the height of the point where it hits the inclined plane from the point of projection.
The path traced by all the three particles is given,
$h_{A} > h_{B} > h_{c}$
Thus,
$v_{A} > v_{B} > v_{c}$

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Three particles are projected from a tower on inclined plane with same speed u as shown in figure. Mark the correct option from the following

Three particles are projected from a tower on inclined plane with same speed $u$ as shown in figure. Mark the correct option from the following