Three particles each of mass M are placed at the corners of a triangle of side length L. About an axis passing through any side of frame the moment of inertia of three bodies is :
A
ML2
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B
3ML22
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C
3ML24
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D
3ML25
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Solution
The correct option is C3ML24 MI of system about a side will have contribution from the only mass which does not lie on this axis. I=M(√32L)2 =34ML2