Three particles of masses 2kg,3kg and 5kg are situated at the vertices of a right angled triangle ΔABC as shown in figure. Find the moment of inertia of the system about line PQ perpendicular to the BC and in the plane of ΔABC.
A
40kg-m2
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B
80kg-m2
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C
32kg-m2
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D
48kg-m2
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Solution
The correct option is B80kg-m2 Given: m1=2kg ; m2=3kg ; m3=5kg r1=4m ; r2=4m ; r3=0m
Total moment of inertia of system I=I1+I2+I3 =m1r21+m2r22+m3r23 =2×42+3×42+5×02 =80kg-m2