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Question

Three persons A, B and C at the corners of an equilateral triangle of side X move at a constant speed V. Each person maintains a direction towards the person at the next corner. The time, the persons take to meet each other is :

A
2X3V
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B
2XV
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C
XV
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D
4X3V
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Solution

The correct option is A 2X3V

When A starts moving towards B, B has already started moving towards C and as B starts moving towards C, C has already started moving towards A, and as C starts moving towards A , A has already started moving towards B.


velocity of A is V along AB

the velocity of B is along BC . its component along BA is Vcos60=V2. thus the separation AB decreases at the rate Vres=V+V2=3V2

since this rate is constant. the time taken in reducing the separation AB from Xto 0 is

time=distancespeed=X3V2=2X3V

856815_2694_ans_6050cdee6d9a4500ba0e5ceaa13c785a.PNG

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