Three persons P, Q and R are standing in a queue. There are five persons between P and Q and eight persons between Q and R. If there be three persons ahead of Rand 18 persons behind P, what could be the minimum number of persons in the queue?

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Solution

The correct option is C 25
As per the information given in the question , person R stands ahead of line, with 3 person ahead of him. There are 8 persons between Q and R. Out of these 8 persons, the third is person P. So this makes 5 persons between P and Q. After P there are 18 more persons.This makes around 25 persons in the line.
Therefore, the minimum number of persons in the queue us 25.
Option C is the correct answer.
__18
| |
S-----3----R--2--P----5---Q--12-----E
|8_|
(S is 1st person and E is end person in queue)

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