Three prime numbers $x, y, z$ has a product $385$ , then sum of their squares is

92

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195

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215

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287

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Solution

The correct option is B $195$
Prime factorization of $385$ is $5 \times 7 \times 11$
$x, y, z = 5, 7, 11$
$\Rightarrow x^{2} + y^{2} + z^{2} = 5^{2} + 7^{2} + 11^{2} = 195$

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