Question

Three processes fom a thermodynamic cycle as shown on P-V diagram for an ideal gas. Process $1\to 2$ takes place at constant temperature (300 K). Process $2\to 3$ takes place at constannt volume. During this process 40J of heat leaves the system. Process $3\to 1$ is adiabatic and temperature $l_2$ is 275K. Work done by the gas during the process $3\to 1$ is

Answer 1

$z-3,$ $\Delta V=\Delta Q$

$\Delta V=-40$

$3-1,$ $\Delta V=\Delta Q^0-\omega$

Here$,$ from $3-1,$ $\Delta V$ is $+40$

$\omega =-40J.$