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Question

Three resistors 1Ω, 2Ω and 3Ω are connected to form a triangle. Across 3Ω resistor a 3V battery is connected. The current through 3Ω resistor is:

A
0.75A
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B
1A
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C
2A
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D
1.5A
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Solution

The correct option is B 1A
The arrangement is shown in figure.
Here, two resistance of 1Ω and 2Ω are in series, which form 3Ω which is in parallel with 3Ω resistance.
Therefore, the effective resistance
(1+2)×3(1+2)+3=32Ω
Current in the circuit,
I=3(3/2)=2A
Current in 3Ω resistor =I2=IA
653474_617575_ans_7f22a37ea79b479fa56f512707526fe3.png

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