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Standard VII

Physics

Displacement

Three ships A...

Question

Three ships A, B & C are in motion. The motion of A as seen by B is with speed $v$ towards north-east. The motion of B as seen by C is speed $v$ towards the north-west. Then as seen by A, C will be moving towards

north

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south

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east

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west

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Solution

The correct option is B south
$_{A B} = v^i + v^j$
$_{B C} = - v^i + v^j$
$∴ {\to V}_{C A} = - {\to V}_{B C} - {\to V}_{A B} = - 2 v^j, i.e. towards south$

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Three ships A, B & C are in motion. The motion of A as seen by B is with speed v towards north-east. The motion of B as seen by C is speed v towards the north-west. Then as seen by A, C will be moving towards

The correct option is B south−−→VAB=v^i+v^j−−→VBC=−v^i+v^j∴→VCA=−→VBC−→VAB=−2v^j, i.e. towards south

Three ships A, B & C are in motion. The motion of A as seen by B is with speed $v$ towards north-east. The motion of B as seen by C is speed $v$ towards the north-west. Then as seen by A, C will be moving towards

The correct option is B south
$_{A B} = v^i + v^j$
$_{B C} = - v^i + v^j$
$∴ {\to V}_{C A} = - {\to V}_{B C} - {\to V}_{A B} = - 2 v^j, i.e. towards south$