Three ships A, B & C are in motion. The motion of A as seen by B is with speed v towards north-east. The motion of B as seen by C is speed v towards the north-west. Then as seen by A, C will be moving towards
A
north
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B
south
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C
east
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D
west
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Solution
The correct option is B south −−→VAB=v^i+v^j −−→VBC=−v^i+v^j ∴→VCA=−→VBC−→VAB=−2v^j, i.e. towards south