Question

Three sides of a triangular field are 20m, 21m, and 29m long, respectively. The area of the field is :

• A. $215m^2$
• B. $230m^2$
• C. $210m^2$
• D. None of these

Answer 1

The correct option is C $210m^2$

Given: Sides of the triangular field; $a=20m,b=21m,c=39m$

Now, Semiperimeter $S=\frac{a+b+c}{2}=\frac{20+21+29}{2}=35m$

$Area=\sqrt{s\times (s-a)\times (s-b)\times (s-c)}$

$=\sqrt{35\times (35-20)\times (35-21)\times (35-29)}$

$=\sqrt{35\times 15\times 14\times 6}$

$=210sq.m$