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Question

Three straight lines L1, L2 and L3 are parallel and lie in the same plane. A total of m points are taken on L1, n points on. L2, k points on L3. The maximum number of triangles formed with vertices at these points are.


A

C3m+n+k

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B

C3m+n+k-C3m-C3n

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C

C3m+n+k+C3m+C3n

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D

None of these

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Solution

The correct option is D

None of these


Explanation for the correct option:

Find the maximum number of triangles:

In the question, it is given that three straight lines L1, L2 and L3 are parallel and lie in the same plane. A total of m points are taken on L1, n points on. L2, k points on L3.

The total number of points are m+n+k.

We know that we have to select 3 point to form a triangle.

Therefore, the total number of ways in which we can select 3 point are C3m+n+k.

Since to form a triangle all the three points cannot be on the same line.

So, the number of ways in which all the three points lie on the same plane can be given by: C3m+C3n+C3k.

The maximum number of triangles can be given by: C3m+n+k-C3m-C3n-C3k.

Therefore, The maximum number of triangles are C3m+n+k-C3m-C3n-C3k.

Hence, option D is the correct option.


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