Three tankers contain 403 litres, 434 litres and 465 litres of diesel respectively. Find the maximum capacity of a container that can measure the diesel of the three containers exact number of times.

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Solution

Maximum capacity of the required tanker = HCF of 403, 434, 465

403 = 13 × 31

434 = 2 × 7 × 31

465 = 3 × 5 × 31

HCF = 31

∴A container of capacity 31 l can measure the diesel of 3 containers exact number of times

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Three tankers contain 403 litres, 434 litres and 465 litres of diesel respectively. Find the maximum capacity of a container that can measure the diesel of the three containers exact number of times.

Maximum capacity of the required tanker = HCF of 403, 434, 465 403 = 13 × 31 434 = 2 × 7 × 31 465 = 3 × 5 × 31 HCF = 31 ∴A container of capacity 31 l can measure the diesel of 3 containers exact number of times

Maximum capacity of the required tanker = HCF of 403, 434, 465

403 = 13 × 31

434 = 2 × 7 × 31

465 = 3 × 5 × 31

HCF = 31

∴A container of capacity 31 l can measure the diesel of 3 containers exact number of times