Question

Three tankers contain $403litres,434litres$ and $465litres$ of diesel respectively. find the maximum capacity of a container that can measure the diesel of the three containers exact number of times.

Answer 1

maximum capacity of the required tanker = HCF of $403,434,465$
$403=13\times 31$
$434=2\times 7\times 31$
$465=3\times 5\times 31$
$HCF=31$
A Container of capacity $31$ I can measure the diesel of $3$ container exact number of times.