Three tankers contain 403 litres, 434 litres and 465 litres of diesel respectively. Find the maximum capacity of a container that can measure the diesel of three containers exact number of times.

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Solution

HCF of two or more number is the highest number which divides the given numbers exactly.
The maximum capacity of container = HCF [403, 434, 465]
Factors of 403 = $13 \times 31$
Factors of 434 = $2 \times 7 \times 31$
Factors of 465 = $3 \times 5 \times 31$
Clearly, HCF = 31
Therefore, 31 litres container is required to measure the diesel of three containers exact number of times.

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