Three times a number added to 8 gives 20. Find the number.

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Solution

Let the required number be x.
Three times this number is 3x.
On adding 8, the number becomes 3x + 8.
3x + 8 = 20
or, 3x + 8 $-$ 8 = 20 $-$ 8 [Subtracting 8 from both the sides]
or, 3x = 12
or, $\frac{3 x}{3} = \frac{12}{3}$ [Dividing both the sides by 3]
or, x = 4
∴ Required number = 4

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Three times a number added to 8 gives 20. Find the number.

Let the required number be x. Three times this number is 3x. On adding 8, the number becomes 3x + 8. 3x + 8 = 20 or, 3x + 8 - 8 = 20 - 8 [Subtracting 8 from both the sides] or, 3x = 12 or, 3x3 = 123 [Dividing both the sides by 3] or, x = 4 ∴ Required number = 4

Let the required number be x.
Three times this number is 3x.
On adding 8, the number becomes 3x + 8.
3x + 8 = 20
or, 3x + 8 $-$ 8 = 20 $-$ 8 [Subtracting 8 from both the sides]
or, 3x = 12
or, $\frac{3 x}{3} = \frac{12}{3}$ [Dividing both the sides by 3]
or, x = 4
∴ Required number = 4