Three unbiased coins are tossed together, then which of the following is true?
The probability of getting exactly two heads is 38
The probability of getting exactly one tail is 38
Total possible cases = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT} (where H= Heads, T= Tails)
Number of exactly 2 heads = {HHT, HTH,THH}
= 3
∴ P (exactly 2 heads) = 38
Number of exactly 1 tail = {HHT, HTH, THH}
= 3
∴ P(exactly one tail) = 38
Number of cases atleast one tail = {HHT, HTH, HTT, THH, THT, TTH, TTT}
= 7
∴ P(at least one tail) = 78