Three vectors a- -b- -c- are such that - a- -1- b- -2- c- -4 and a- -b- -c- -0- Then the value of a- -b- -3b- -c- -3c- -a- is equal to -

The correct option is A 26 c= #160; a b ∴ 4(a b #160; ) +3( b.c )+3( c. a) = 4( a. b)+3 b.( a b)+ 3(a.( a b #160; =4( a. b # ...

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Applications of Dot Product

Three vectors...

Question

Three vectors $\to a, \to b, \to c$ are such that $| \to a | = 1, ∣ ∣ \to b ∣ ∣ = 2, | \to c | = 4$ and $\to a + \to b + \to c = \to 0$ . Then the value of $\to a . \to b + 3 \to b . \to c + 3 \to c . \to a$ is equal to :

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Similar questions

\to a, \to b, \to c

\to a + \to b + \to c = \to 0

(\to a, \to b) = \frac{π}{3}

| \to a \times \to b | + | \to b \times \to c | + | \to c \times \to a | =

\to a, \to b, \to c

\to a + \to b + \to c = \to 0

(\to a, \to b) = \frac{π}{3}

∣ ∣ \to a \times \to b ∣ ∣ + ∣ ∣ \to b \times \to c ∣ ∣ + | \to c \times \to a | =

(\to a \times \to b) \times \to c = \to a \times (\to b \times \to c)

\to a, \to b

\to c

\to a . \to b \neq 0, \to b . \to c \neq 0

\to a

\to c

\to a, \to b, \to c

\to a . \to b = \to a . \to c, \to a \times \to b = \to a \times \to c, \to a \neq 0

\to b = \to c

\to a, \to b, \to c

\to a \times \to b = \to c, \to b \times \to c = \to a, \to c \times \to a = \to b

| \to a | = | \to b | = | \to c |

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